Incorrect output using find command

Shell Programming and Scripting
1

I'm using the below command to list files older than 2 hours but it returns redundant output, am I missing something.

# find . -mmin +120 -exec ls -l {} \;
total 0
-rw-r--r-- 1 root system 0 Oct 13 09:52 test1
-rw-r--r-- 1 root system 0 Oct 13 09:52 test2
-rw-r--r-- 1 root system 0 Oct 13 09:52 test3
-rw-r--r-- 1 root system 0 Oct 11 23:02 dec7
-rw-r--r-- 1 root system 0 Oct 13 09:52 ./test1
-rw-r--r-- 1 root system 0 Oct 13 09:52 ./test2
-rw-r--r-- 1 root system 0 Oct 13 09:52 ./test3
-rw-r--r-- 1 root system 0 Oct 11 23:02 ./dec7

Thanks

2

Look at the output without using ls. That should tell you the answer.

(Hint: use -type f.)

3

find . -type f -mmin +120 -exec ls -l {} \; -->worked.

Thanks for your prompt response but still wondering why I need to specify '-type f' (type file), it complains only while using -mmin flag and not when using -mtime flag because the below code works for me and I'm not using '-type f'

ls -il | awk ' !/total/ {print $1}' | while read ln
do
find . -inum $ln -mtime +1 -exec rm -f {} \;
done

4

Did you look at the output of find without using -exec ls -l {} \;?

That will give you the answer.

5

Because ls -il does not decend into sub directories.

find . decends into directories and sees . as a directory, which is actually current directory.

6

oh..ok, got it, much thanks to Johnson and Ikon