Include pathname in awk output?

Shell Programming and Scripting
1

I am running an awk to verify all the memory settings for tomcat, and need to include path or directory in output ....

I am running:

awk '{ print $3 }' /opt/dir1/dir2/*/tomcat/bin/setenv.sh

Output results:

-Xms1024m
-Xmx1536m
-Xmx1536m
-Xmx1024m
-Xms1024m
-Xms1024m
-Xms512m
-Xms1024m
-Xms1536m
-Xms512m
-Xmx1024m
-Xmx1024m
-Xmx1024m

Is there something I can include in my command that would include the specific directory for '*' in the output?

Like so:

-Xmx1024m /dir3

Where dir3 would be * in /opt/dir1/dir2/*/tomcat/bin/setenv.sh

Or am I going about this completely wrong? :confused:

2

FILENAME would be /opt/dir1/dir2/whatever/tomcat/bin/setenv.sh.

awk '{ X=FILENAME;  sub(/\/opt\/dir1\/dir2\//, "", X); sub(/\/tomcat\/bin\/setenv[.]sh/, "", X);  print X, $3 }' /opt/dir1/dir2/*/tomcat/bin/setenv.sh
1 Like
3

Please use code tags as required by forum rules!

man awk :

awk '{print FILENAME}' /opt/dir1/dir2/*/tomcat/bin/setenv.sh

You can't find out the position of "*" in your input string as it will be expanded by the shell long before awk gets hands on it.

4

Thank you Corona688! Your solution worked for me!