Hi All,
I am using below if condition to check whether null is passed as a parameter to the program
if ["$3"="null"] or ["$4"="null"];
then
echo "ABC">>$FILE
else
echo "CDF">>$FILE
fi
However it is saying me null=null command not found . Please help me with this
Hello Hypesslearner,
Could you please try following and let me know if this helps.
if [[ "$3"="null" || "$4"="null" ]]
then
echo "ABC" >> "$FILE"
else
echo "CDF" >> "$FILE"
fi
Thanks,
R. Singh
Just querying:-
Are you sure you are looking for the four ASCII characters 'null' or do you really mean "" as a null.
If so this might be what you are looking for:-
if [ "$3" = "" ] || [ "$4" = "" ]
I am looking for 4 ascii characters and its working now with above code . Thanks all .
Have a try with:
[ -z "$3$4" ] && echo "Var 3+4 are empty"
[ 3 -eq $# ] && echo "Script has 3 args"
echo "Arg 1 has ${#1} Chars
Note that [[ condition ]] is called bashism, as it allows the 'not using' quotes, which is bad for code portability.
Instead, try to get used to [ condition ] which requires proper quoteing but beeing POSIX standard, it is much more compatible among different shells.
Hope this helps
Parameter checking is not working
I am passing as below
$2=ABC and $3,$4 as empty but this is executing step1
if [["$2"!="" && "$3"!="" && "$4"!=""]]
then
echo "Execute step1
else
echo "Execute step2"
fi
Separate all the quoted strings with spaces from their neighbourhood.
Still it is executing step1 only
if [["$2"!=" " && "$3"!=" " && "$4"!=" "]]
then
echo "Execute step1
else
echo "Execute step2"
fi
You did NOT separate ALL quoted strings from ALL their neighbours by inserting spaces!
---------- Post updated at 15:58 ---------- Previous update was at 15:58 ----------
Actually, you inserted spaces into the empty strings which is not what you wanted.
Yes Got it now and here it looks like
if [[ "$2" != "" && "$3" != "" && "$4" != "" ]]