If 2nd column is matched

Shell Programming and Scripting
1

Both codes not working for me.

whois nba.com| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com.pt| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com.pt| sed -n '/Registry Admin ID:/,/Admin Email:/p' 
whois ymas.com.pt| sed -n '/Registry Tech ID:/,/Tech Email:/p' > 
whois ymas.com.uy| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com.uy| sed -n '/Registry Admin ID:/,/Admin Email:/p' 

cat aa.sh|awk -F. '$2 == "com|"  {print $0}'
 
cat aa.sh|awk -F. '$2 == "com"  {print $0}'

Desired output

whois nba.com| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com| sed -n '/Registry Registrant ID:/,/Registrant
2

If the separator is . then the field (#2) ends at the next . or at the end of the line.
You can do an ERE-search:

awk -F. '$2 ~ /com|/ {print $0}' aa.sh

or limit the search to the beginning of the field

awk -F. '$2 ~ /^com\|/ {print $0}' aa.sh

In the latter case I have escaped \| because | is a special ERE character unless at the very beginning or the very end or within [ ].

1 Like
3

cool,

this works for me

awk -F. '$2 ~ /^com\|/ {print $0}'

---------- Post updated at 10:51 AM ---------- Previous update was at 10:49 AM ----------

but there is what if,,,

waht if the "|" is not existing,

out code works only because of "|" it can fetsh easily

4

How about

awk '!/com\./' file
whois nba.com| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com| sed -n '/Registry Registrant ID:/,/Registrant

---------- Post updated at 17:41 ---------- Previous update was at 17:40 ----------

... or even better

awk '/com[^.]/' file
whois nba.com| sed -n '/Registry Registrant ID:/,/Registrant 
whois ymas.com| sed -n '/Registry Registrant ID:/,/Registrant
1 Like
5

this is not working on general

awk '!/com\./'

this is the right answer of all,

awk '/com[^.]/'
6

Still a

awk '/[.]com\|/'

or

awk '$2 ~ /[.]com\|/'

is more precise, just like the previous one with dot-separated fields.
--
A correction: the | should be escaped \| even at the beginning or end.
Otherwise certain awk versions match everything, and other awk versions give an ERE error.