I need help to compare file name with regular expression and do something with file

Shell Programming and Scripting
1 
#!/bin/sh
Today=date '+%Y%m%d' 
for file in `ls *.csv *txt` 
do          
        echo "Start woprking with ${file}"
         if [ "${file}" = "*_${Today}*" ];  then
                 do something
         elif [ "${file}" = "*.${Today*}" ];  then
               do something 
               else
                   echo "Unkniowned file name"
               fi
        fi
done

Files names like this:

asd_ajfh_kjghjkg_20170227.csv
asd_ajfh_kjghjkg.20170227.csv
iytouy_jkhk_jghfadj_123_6453_20170227_U.csv

Script print first line before first if and doing nothing. Can somebody let me know where I am wrong? I am on AIX, korn, born, or c

I need it because depends of _Today .Today files will be processed differently

2

Why not only select the files that match your required pattern when listing the files in the first place? This might get you started:-

#!/bin/ksh
Today=`date '+%Y%m%d'`
for file in *[._]${Today}*
do
   something with "${file}"
done

Note that I've added ` around the date command. Although I think this is deprecated, I'm not sure if your shell will support the $(date '+%Y%m%d') form.

Are there any files with spaces in the name that we have to handle?

Does this help?
Robin

3

I have 70 different files. Some of them are: XXX_Today.csv , some of them XXXX.Today.csv . All of them can have different amount of XXXXX (fro 2 to 5) divide by _. The main problem is that I have to find the file, find Today and cut it from the main part, and what has left, for example XXX_CCCC_BBBB I open file find this part and make short form, like XCB and son on. I will check about Today , may be you are right. I will let you know as soon as I get to work

4

How would iytouy_jkhk_jghfadj_123_6453_20170227_U.csv fit into that scheme?

5

Do you have another solution?

---------- Post updated at 09:26 AM ---------- Previous update was at 08:53 AM ----------

Yes, my shell handle this format and before catch file I print ${Today} and it show me 20170228

---------- Post updated at 09:35 AM ---------- Previous update was at 09:26 AM ----------

Robin

Note that I've added ` around the date command. Although I think this is deprecated, I'm not sure if your shell will support the $(date '+%Y%m%d') form.

Are there any files with spaces in the name that we have to handle?

Yes, my shell handle this format and before catch file I print ${Today} and it show me 20170228

Oleg

6

Guessing from your original code that you only want to process files with names ending with .csv or .txt , I would tend to try something like:

#!/bin/ksh
Today=$(date '%Y%m%d')
for file in *$Today*.csv *$Today*.txt
do	if [ -f "$file" ]
	then	echo do whatever with "$file"
	fi
done

or if you know that you won't encounter filename extensions like cxt and cst , you could shorten:

for file in *$Today*.csv *$Today*.txt

to:

for file in *$Today*.[ct][sx][vt]
7

No,
I need files *${Today}*.csv *${Today}.txt
and *.${Today}.csv *.${Today}*.txt

For the second line I made a loop and it is perfectly fine.
The first line is still there are still a lot of questions, because I don't know the precise files names. When I find out, I will ask for help