Hi,
I have 2 sub routines for example.
use Benchmark 'cmpthese';
sub explicit {
print "\n print and calculate\n";
}
sub new_per_loop {
for (0..4){
print "\n print the loop \n";
}
}
cmpthese (10_000, {
'Explicit' => &explicit,
'New Array Per Loop' => &new_per_loop,
}
);
It is going to an infinite loop and cmpthese function what should be the count?
What is the default count?
I tried to understand through Google but i did not get a clear picture?
In the real scenario i have to apply bench mark and calculate the time taken for a bigger sub routine which has many loops.
How can i put this bench mark to calculate the time taken by the sub routine?
If u can provide me the clear picture with an example that would be really great.
Regards
vanitha
Not that I know PERL much, but Benchmark - perldoc.perl.org says:
cmpthese - print results of timethese as a comparison chart
and:
# cmpthese can be used both ways as well
cmpthese($count, {
'Name1' => '...code1...',
'Name2' => '...code2...',
});
cmpthese($count, {
'Name1' => sub { ...code1... },
'Name2' => sub { ...code2... },
});
# ...or in two stages
$results = timethese($count,
{
'Name1' => sub { ...code1... },
'Name2' => sub { ...code2... },
},
'none'
);
cmpthese( $results ) ;
I suggest the first form with no & and in single quotes.
HI,
I tried these but could not get the results.
I have to identify the sub routine which is taking a lot of time.
But i am unable to trace which part of the sub routine.
If u can help me out with this that would be really great.
REgards