In Redhat it is easy....
date --date="60 minutes ago"
How do you do this in Solaris?
I got creative and got the epoch time but had problems..
EPOCHTIME=`truss date 2>&1 | grep "time()" | awk '{print $3 - 900}'`
echo $EPOCHTIME
TIME=`perl -e 'print scalar(localtime("$EPOCHTIME")), "\n"'`
echo $TIME
The output from "echo $EPOCHTIME" is correct however the output from "echo $TIME" is not correct. The $EPOCHTIME variable does not carry over.
That's because nothing expands inside single quotes.
Why not just do the entire thing in perl? time() gets you current time in epoch seconds.
My perl is about nonexistent.. LOL. I will look into it though.
Right from perldoc -f time you get this:
use POSIX qw(strftime);
$str=strftime "%a %b %e %H:%M:%S %Y", localtime;
which you can adapt into this:
perl -e 'use POSIX qw(strftime); print strftime "%a %b %e %H:%M:%S %Y\n", localtime(time()+$ARGV[0]);' -- -3600
The -3600 is the number of seconds to add, negative one hour.
That is a nice one liner.. Thank you sir.
I wouldn't call anything two terminal screens wide a "one-liner", but you're welcome.