How to see a variable value outside a function in kshell

Shell Programming and Scripting
1

Hi,

I wrote a small shell script which had function C_fun() and script name is same C_fun.ksh

Here is the program inside the script

#!bin/ksh -x
C_fun()  {
  typeset TEXT=${1}
}
echo Value of TEXT $TEXT

When Im running the above script with Parameter "R" as the option . The echo statement is not throwing me a value
The output is echo Value of TEXT and there is no value available "R" . How can I catch the variable value outside the function. I tried with export option instead of typeset but no help. I Want to catch the value of the $TEXT outside the function. I hope some one can help me in this.

Thanks,
Raju.

2

You can get at the variable in a number of ways: -

#! /bin/ksh -x

C_fun() {
        TEXT=$1
}

C_fun test 

echo "Value of TEXT = $TEXT"

#! /bin/ksh -x

C_fun() {
        eval ${2}=${1}
}

C_fun test TEXT

echo "Value of TEXT = $TEXT"
3

Hi Raju,

A few remarks:

  1. The shebang is wrong and should be
    text #!/bin/ksh
  2. Your script is not calling the function C_fun so the variable TEXT never gets set
  3. You are using the typeset declaration which declares a variable as local to the function, so in fact you are demanding that the variable be unknown outside the function.
  4. You'll discover that the variable is global anyway, since you are using the posix style function declaration: (
    text fn(){ ... }
    instead of the ksh style:
    text function fn{ ... }
  5. If you are using ksh93 you could use nameref instead of eval
#!/bin/ksh
C_fun() {
  typeset TEXT=${1}
}
echo Value of TEXT $TEXT

Value of TEXT
----
#!/bin/ksh
C_fun() {
  typeset TEXT=${1}
}
C_fun test
echo Value of TEXT $TEXT

Value of TEXT test
----
#!/bin/ksh
C_fun() {
  TEXT=${1}
}
C_fun test
echo Value of TEXT $TEXT

Value of TEXT test
----
#!/bin/ksh
function C_fun {
  typeset TEXT=${1}
}
C_fun test
echo Value of TEXT $TEXT

Value of TEXT
----
#!/bin/ksh
function C_fun {
  TEXT=${1}
}
C_fun test
echo Value of TEXT $TEXT

Value of TEXT test
----
#!/bin/ksh
function C_fun {
  nameref var=$2
  var=$1
}
C_fun test TEXT
echo Value of TEXT $TEXT

Value of TEXT test
4

Hi Guys,

Thanks for your help it is working fine if I do as you said

#!/bin/ksh
C_fun() {
  typeset TEXT=${1}
}
C_fun ${1}
echo Value of TEXT $TEXT

I have one more question on this. How can I Pass multiple parameters to a function above I'm passoing C_fun ${1} only . I want to pass $2 also as an parameter to a function I tried by placing comma like C_fun ${1},${2} but this is giving me Value of Text F,Fail. How to pass multiple parameters to a function and see its value.

---------- Post updated at 04:51 PM ---------- Previous update was at 04:45 PM ----------

Here is my script

#!/bin/ksh
C_fun() {
typeset TEXT=${1}
typeset  Stat=${2}
}
C_fun ${1},${2}
echo Value of TEXT $TEXT
echo Value of Stat $Stat

But it is giving me

Value of TEXT F,Fail
Value of Stat

Value of Stat is empty I need to get its value as Fail and Text Value as F since $1 is F and $2 is Fail

I think this post will be more clear then previous one.

Thanks,
Raju.

5 
#!/bin/ksh
C_fun() {
  TEXT=$1
  Stat=$2
}
C_fun "That was fun" "While it lasted"
echo Value of TEXT $TEXT
echo Value of Stat $Stat

Value of TEXT That was fun
Value of Stat While it lasted

#!/bin/ksh
C_fun() {
  TEXT=$1
  Stat=$2
}
C_fun food barf
echo Value of TEXT $TEXT
echo Value of Stat $Stat

Value of TEXT food
Value of Stat barf
6

?????

The correct shebang is: #!/bin/ksh

A shebang is a comment and starts with #.

7

Thanks! I corrected the typo...