how to retreive certain section of the line

Shell Programming and Scripting
1

Hi
I am using "grep" command to get certain pattern out of the file:
PNUM=34
$ grep -w "#${PNUM}" myfile
#34 * 2297 * 410 * 964 * * 4352
$

Is there a way to retrieve the section of the above output without #34 so the output would look like this:
* 2297 * 410 * 964 * * 4352

Thanks

2

try:

echo "#34 * 2297 * 410 * 964 * * 4352" | sed -n '/#34/ s/#34//p'
3

Awk script (snip.awk):

{
        for( i = 1; i <= NF; i++)
                if ( $i !~ /#34/ )       # your pattern goes here
                        printf "%s ", $i
        printf "\n"
}

Data file (myfile):

#34 * 2297 * 410 * 964 * * 4352
#44 * 244 * 43 * 4 4 4
#55 * #34 * * * * ddd * *

Output:

# awk -f snip.awk myfile
* 2297 * 410 * 964 * * 4352 
#44 * 244 * 43 * 4 4 4 
#55 * * * * * ddd * *
4

Shorter :rolleyes:

# PNUM=34

# awk  '{sub("^#'$PNUM' ","")}1' file
* 2297 * 410 * 964 * * 4352
#44 * 244 * 43 * 4 4 4
#55 * #34 * * * * ddd * *

# sed "s/^#$PNUM //" file
* 2297 * 410 * 964 * * 4352
#44 * 244 * 43 * 4 4 4
#55 * #34 * * * * ddd * *