How to replace a line

Shell Programming and Scripting
1

I have a line which starts with Default "heresometext" and i want to replace that line with Default "".

Can any one please give me how to acheive this.

Thanks

2

echo "heresometextabcd" | sed 's/heresometext//'

3

It works...

> echo 'Default "here Sometext" '                                                          
Default "here Sometext" 
> echo 'Default "here Sometext" ' | tr '"' '~' | sed 's/~[ A-Za-z]\{0,20\}/~/' | tr '~' '"'
Default ""

Explanation:
echo out your statement with the " displayed
change " to ~ (sometimes " are difficult to deal with)
take the first ~ and up to 20 characters and replace with just a ~
change the two ~ back to "
VOILA, DONE.

There would be simpler ways if you knew what was inside the ", or to simply force an answer. However, I figured you were trying to program a variable situation (up to 20 characters) to accomplish the task.