How to read a subfolder one by one in parent folder?

Shell Programming and Scripting
1

Hi friends,

               I am getting some trubles in folder reading. I am having 10 subfolders inside server7 folder. i wanna to read a subfolder name first and check if the foldername gets started with "http". if so , i need to read a file inside that folder. This willl continue for that 10 folders and quit after read the all subfolders. for the abov e requirement i wrote code like this

for file in /x/y/server/* ;
do
start=`echo $file | cut -d "-" -f 1`
if [ $start == "http" ]
then
cd /x/y/server/$file/config
if [ -f filename ]
then
size=`ls -ltr filename awk '{print $5}' `
if [ $size == 0]
then
echo " The size of $filename is $size . "

here i gave only the fubctionality.

But i am to read very first folder only. I am not able to read rest of the folder.

can anyone help me for this...
Thanks in advance..

2
  1. Use 'find' utility (that seems to be the answer for your question)
  2. Imagine a file with name some tricky $name$ with
    newline characters
    and think how your code would work like... In fact how it would NOT work :smiley:
  3. Try using high level shell (you have not specified whether this is a HTML document or shell code or whatever) like ksh,bash,zsh,etc. Then provide "magic number" in the first line.
  4. If using a high level shell - use [[ ]] instead of [ ]
  5. I tend to use ksh with $() in place of `` - think about `ls `cat pattern_file`` (you can do $(ls $(cat pattern_file)) )
  6. If using ksh - try using print instead of echo
  7. Avoid nested code (someone told me that writing a lot of if's is not a bad thing... but some other man told me to avoid if's whenever possible - the second one gave me a good advice while the first one wasted my time)
  8. If you are using a high level shell then try using "${var}",'${var}' instead of what you wrote