How to print the output side by side?

Hello,
I know it is too simple but I do not know..

#!/bin/bash
for file in *.mp4
do
echo "$file"
ffmpeg -i $file 2>&1 | grep Duration |cut -d ' ' -f 4 | sed s/,//
done

Expected Output:

NF_-_Let_You_Down-fbHbTBP_u7U.mp4	00:03:35.74
NF_-_WHY-zuJV-DAv_wE.mp4	00:03:11.87
Nicki_Minaj_-_Chun-Li-Wpm07-BGJnE.mp4	00:05:09.41
Nicki_Minaj_-_Chun-Li_Vertical_Video-SCq8n_hOcN8.mp4	00:03:21.67
Post_Malone_-_Psycho_ft._Ty_Dolla_ign-au2n7VVGv_c.mp4	00:03:56.64

It gives:

NF_-_Let_You_Down-fbHbTBP_u7U.mp4
00:03:35.74
NF_-_WHY-zuJV-DAv_wE.mp4
00:03:11.87
Nicki_Minaj_-_Chun-Li-Wpm07-BGJnE.mp4
00:05:09.41
Nicki_Minaj_-_Chun-Li_Vertical_Video-SCq8n_hOcN8.mp4
00:03:21.67
Post_Malone_-_Psycho_ft._Ty_Dolla_ign-au2n7VVGv_c.mp4
00:03:56.64

I'd like to do it without transposition or convertion row to column etc.

Many thanks
Boris

sample output of ffmpeg -i $file 2>&1 please.

Here you are:

ffmpeg version N-91591-g1581caa Copyright (c) 2000-2018 the FFmpeg developers
  built with gcc 4.8 (Ubuntu 4.8.4-2ubuntu1~14.04.4)
  configuration: --prefix=/root/ffmpeg_build --pkg-config-flags=\
--static --extra-cflags=-I/root/ffmpeg_build/include --extra-ldflags=\
-L/root/ffmpeg_build/lib --extra-libs='-lpthread -lm' --bindir=/root/bin --\
enable-gpl --enable-libfdk-aac --enable-libfreetype --enable-libmp3lame --\
enable-libopus --enable-libvorbis --enable-openssl --enable-libvpx \
--enable-libx264 --enable-libx265 --enable-nonfree
  libavutil      56. 18.102 / 56. 18.102
  libavcodec     58. 22.101 / 58. 22.101
  libavformat    58. 17.101 / 58. 17.101
  libavdevice    58.  4.101 / 58.  4.101
  libavfilter     7. 26.100 /  7. 26.100
  libswscale      5.  2.100 /  5.  2.100
  libswresample   3.  2.100 /  3.  2.100
  libpostproc    55.  2.100 / 55.  2.100
Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'YG_-_Big_Bank_Audio_ft._2_Chainz_Big_Sean_Nicki_Minaj-scLYjsvrUMk.mp4':
  Metadata:
    major_brand     : isom
    minor_version   : 512
    compatible_brands: isomiso2avc1mp41
    encoder         : Lavf58.17.101
  Duration: 00:03:59.38, start: 0.000000, bitrate: 203 kb/s
    Stream #0:0(und): Video: h264 (High) (avc1 / 0x31637661), yuv420p(tv, bt709), 1920x1080 [SAR 1:1 DAR 16:9], 71 kb/s, 23.98 fps, 23.98 tbr, 90k tbn, 47.95 tbc (default)
    Metadata:
      handler_name    : VideoHandler
    Stream #0:1(eng): Audio: aac (LC) (mp4a / 0x6134706D), 44100 Hz, stereo, fltp, 125 kb/s (default)
    Metadata:
      handler_name    : SoundHandler

ffmpeg -i $file 2>&1 | awk -F'[ ,]' -v f="${file}" '/Duration/ {print f, $4}'

and remove echo "$file" from inside the loop.

The issue of the unwanted format is echo "$file". The echo has an implicit appended newline.

Here's a fix without much change to your code

duration=$(ffmpeg -i $file 2>&1 | grep Duration |cut -d ' ' -f 4 | sed s/,//)
echo "$file $duration"

Another would be to use printf

printf "%s " $file
ffmpeg -i $file 2>&1 | grep Duration |cut -d ' ' -f 4 | sed s/,//

I like not to choose heavier utilities like awk or sed that could do the whole work without any external help if I have committed to use a filtering technique.

duration=$(ffmpeg -i $file 2>&1 | grep Duration |cut -d ' ' -f 4)
printf "%s %s\n" $file ${duration%,}

Hello Vgersh,
it works as expected.
Thank you so much.

Dear Aia,
I liked below one:

duration=$(ffmpeg -i $file 2>&1 | grep Duration |cut -d ' ' -f 4 | sed s/,//)
echo "$file $duration"

Thank you both

Kind regards
Boris

OK, then we can do better in removing the extraneous comma

duration=$(ffmpeg -i $file 2>&1 | grep Duration |cut -d ' ' -f 4)
echo "$file ${duration%,}"

How about

ffmpeg -i $file 2>&1 | awk -F"[', ]" '/Input/ {printf "%s\t", $(NF-1)} /Duration/ {print $4}'
YG_-_Big_Bank_Audio_ft._2_Chainz_Big_Sean_Nicki_Minaj-scLYjsvrUMk.mp4	00:03:59.38