How to print only lines in between two strings using awk

Shell Programming and Scripting
1

Hi,

I want to print only lines in between two strings and not the strings using awk.

Eg:
OUTPUT
top 2
bottom 1
left 0
right 0
page 66
END
I want to print into a new file only
top 2
bottom 1
left 0
right 0
page 66

Thanks in Advance
JS

2

awk /OUTPUT/,/END/ filename|grep -v 'OUTPUT^JEND'

or

awk /OUTPUT/,/END/ filename|grep -v 'OUTPUT
END'

3

there's a standard algo for doing this. turning on/off a flag

f=0
while read line
do
 case $line in 
  OUTPUT*) f=1; continue ;;
  END* ) f=0
 esac
 if [ "$f" -eq 1 ]; then
    echo $line 
 fi
done < "file"
4

In awk:

awk ' /OUTPUT/ {flag=1;next} /END/{flag=0} flag { print }' file
5

Hi,

I think this one is easy.

sed -e '1,/OUTPUT/d' -e '/END/,$d' file
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