How to print a % within a printf() function using awk

Here is the code I'm using

{
printf("%11d %4.2f\% %4.2f\%\n", $1,$2,$3);
}

I want the output to look something like

1235415234 12.24% 52.46%

Instead it looks something like

319203842 42.27\%4.2f\%

How do I just print a "%" without awk or printf thinking I'm trying to do something. Blackslash escapes don't seem to work.

use %% insead of \%