how to pass variables to s3cmd in a script file

Shell Programming and Scripting
1

Hi All,

How to pass the variable to s3cmd put command? I'm trying to use this command in a script as below:

s3cmd put ${upload_path} s3://${upload_dest}

where

With the above command in script, the file is not getting uploaded.
Please help!!!

2

You might need test.file on the end of the upload destination there.

Does it print any error messages?

3

if I try the command outside of the script as below, it is working fine:

s3cmd put /home/eng/test.file s3://mybucket/
4

Show your entire script. Maybe your variables aren't being set correctly.

5

Here you go!!

        echo "Selected the option to Upload file"
        echo " "
        echo "Provide the complete path of the filename to upload to s3"
        read upload_path
        echo " "
        echo "List of Buckets:"
        s3cmd ls
        echo " "
        echo "Provide the destination bucket details to upload: "
        read upload_dest
        echo " "
        echo "source path : ${upload_path}"
        echo "dest path: ${upload_dest}"
        s3cmd put ${upload_path} s3://${upload_dest}