How to pass C array as input to Shell script

Applications Programming
1

Hi,

In the below C code , i  want to pass the array to a unix shel script.

my script should called as ex myscript 1,2,3

#include <stdio.h>
int main()
{
int a[2]={1,2,3};
}

Thanks,
Arun

2

Code tags for code please.

```text
 stuff 
```

without the extra spaces in the tags.

Your array is too big. You specify that it has two elements but give it three initializers. This probably produces a warning.

To do what you want you need to convert it into a string. If it will always just have three initializers it could probably be made simpler but this should work for any size of array.

#include <stdio.h>
// for execlp()
#include <unistd.h>

int main()
{
  const char *script="echo";
  const char *prefix="";
  int pos=0, n;
  char buf[256];
  int a[3]={1,2,3};

  for(n=0; n<3; n++)
  {
    pos+=snprintf(buf+pos, 256-pos, "%s%d", prefix, a[n]);
  }
  printf("will call %s with %s\n", script, buf);

  // Note that this command never returns unless it fails to run at all.
  execlp(script, script, buf, NULL);
  // If the program is still running, then execlp failed, so return error
  return(1);
}