How to grep a word and next column to that word?

Shell Programming and Scripting
1

Hi,

I have input file as below. Can you help me?

inac_4y;0;2;Balance;200;1;1; 
0;2;Balance;100;1;   
0;inac_nq;0;1;Balance;100;1

desired output

Balance;200
Balance;100
Balance;100

-Suresh

2 
$> sed 's/.*\(Balance;[^;]*\);.*/\1/' infile
Balance;200
Balance;100
Balance;100
3 
grep -Eo 'Balance;[0-9]{3}' infile
4 
#!/bin/bash
# bash 3.2+
while read -r line
do
    [[ $line =~ (Balance;.[^;]*) ]]
    echo ${BASH_REMATCH[0]}
done < inputfile
5 
perl -wlne '/.*(Balance)(\;\d+).*/ and print $1,$2'  infile.txt
6 
$ awk -F \; '{for (i=1;i<=NF;i++) if ($i~/Balance/) print $i FS $(i+1)}' infile

Balance;200
Balance;100
Balance;100