how to grep a file and cut a corresponding value from the line

i have to grep a file which has contents like

/Source/value/valuefile/readme.txt DefaultVersion:=1.7

I have to grep this file with "/Source/value/valuefile/readme.txt" and cut the corresponding value "1.7" from the same line

i tried grep and cut but not working.

in awk and if your file is in the same format as the given example then you could try this

awk -F"=" '/\/Source\/value\/valuefile\/readme.txt/ {print $2}' filename

or with grep and cut

grep "/Source/value/valuefile/readme.txt" filename|cut -d"=" -f2