How to get the parameter value from the parameter file in perl?

Shell Programming and Scripting
1

hi all,
i have a parameter file of following format, i want a method which can get the value of specific parameter.
parameter file format:

<Parameter Name="FileLocationWindows">
                <Description>
                    The directory location of the logger file.
                </Description>
                <Type>String</Type>
                <Restriction>
                    <RequiresRestart>false</RequiresRestart>
                    <Level>1</Level>
                    <MinVal/>
                    <MaxVal/>
                    <MaxLength>1000</MaxLength>
                    <Mandatory>true</Mandatory>
                    <Lov/>
                </Restriction>
                <Value>
                    <Item Value="logs"/>
                </Value>
            </Parameter>
            <Parameter Name="FileLocationUnix">
                <Description>
                    The directory location of the logger file.
                </Description>
                <Type>String</Type>
                <Restriction>
                    <RequiresRestart>false</RequiresRestart>
                    <Level>1</Level>
                    <MinVal/>
                    <MaxVal/>
                    <MaxLength>1000</MaxLength>
                    <Mandatory>true</Mandatory>
                    <Lov/>
                </Restriction>
                <Value>
                    <Item Value="/var/cti/logs/sitebook"/>
                </Value>
            </Parameter>

for example the value of parameter FileLocationUnix is /var/cti/logs/sitebook.

i want a method (getParameterValue("paramtername","parameterFileLocation")) which will return the value.
please help.

2

Take a look at perl's XML::XPath module.