How to get the number series in between?

Shell Programming and Scripting
1

Hi Guys,

Can someone give me a simple script that can extract the numbers in between numbers from start to end. As shown below, it start from 100 to 110 and revealed the numbers in between.

INPUT:

100 - 110

DESIRED OUTPUT:

100
101
102
103
104
105
106
107
108
109
110

Thanks in advance.

Br,
Pinpe

2

Here is one way of doing it:

#!/usr/bin/ksh
mFrom=$1
mTo=$2
typeset -i mCnt=${mFrom}
while [[ ${mCnt} -ge ${mFrom} && ${mCnt} -le ${mTo} ]]; do
  echo "${mCnt}"
  mCnt=${mCnt}+1
done

Run it as "myscript From To".

1 Like
3

Hi,

Test next 'perl' script:

$ cat script.pl
use strict;
use warnings;

my $input = join " ", @ARGV;
my ($min, $max) = $input =~ /^\s*(\d+)\D+(\d+)\s*$/ or 
        die "Usage: perl $0 [number] - [number]\n";

print $_, "\n" for ( $min .. $max );
$ perl script.pl 100 - 110
100
101
102
103
104
105
106
107
108
109
110

Regards,
Birei

4

Perfect! Thanks dude! :b: :slight_smile:

Br,
Pinpe

5

ksh, bash:

echo {100..110} | tr ' ' '\n'

with seq utility

seq 100 110
6 
#!/bin/ksh93

for (( mCnt=$1, mTo=$2; mCnt <= mTo; mCnt++ )); do
   echo $mCnt
done
7

Using awk:

echo '100 110' | awk '{while($1<=$2)print $1++}'