How to get the count only if two column matches?

Shell Programming and Scripting
1

Hi,

I have a file with the contents as below,

10:23:10        GOOD      10.30.50.60
10:23:11        GOOD      10.30.50.62
10:23:12        Hello        10.30.50.60
10:23:12        BAD         10.30.50.60
10:23:13        GOOD       10.30.50.66
10:23:14        BAD         10.30.50.62
10:23:15        Hello        10.30.50.66
10:23:16        Hello        10.30.50.66
10:23:16        BAD         10.30.50.66

I need the output like this,

No of Hello for  10.30.50.60: 1
No of Hello for  10.30.50.66: 2

Also

No of Hello for 10:23 (time) : 3

Please anyone suggest a script for this.

Thanks in advance

2 
$ awk '$2=="Hello" {count["Number of "$2" for "$3]++}END{for(j in count) print j":",count[j]}' gobi1.txt
Number of Hello for 10.30.50.60: 1
Number of Hello for 10.30.50.66: 2

//Jadu

3

And,

$ awk '$2=="Hello" {count["Number of "$2" for "substr($1,1,5)]++}END{for(j in count) print j"(time):",count[j]}' gobi1.txt
Number of Hello for 10:23(time): 3

//Jadu

4

Or:

awk '{a[$4 " in " $5]++
      b[$4" for "$1":"$2]++;next}
END{
for ( i in a )
   print "No of "i":" a
print "---------------------------"
for ( i in b )
   print "No of "i"(time):" b

}' FS="( )|(:)"file
No of GOOD in 10.30.50.60:1
No of GOOD in 10.30.50.62:1
No of GOOD in 10.30.50.66:1
No of BAD in 10.30.50.60:1
No of Hello in 10.30.50.60:1
No of BAD in 10.30.50.62:1
No of BAD in 10.30.50.66:1
No of Hello in 10.30.50.66:2
---------------------------
No of Hello for 10:23(time):3
No of BAD for 10:23(time):3
No of GOOD for 10:23(time):3