How to get last record?

Shell Programming and Scripting
1

Hello all,

I have an out put of

ls -l

as follow :

drwxr-xr-x 3 pipeline pipeline 4096 Jun 15  2011 mongodb-linux-x86_64-1.8.2
drwxr-xr-x 3 root     root     4096 Feb 27  2012 mongodb-linux-x86_64-2.0.3

now i would like to get 2.0.3

i have tred this and it did not work

ls -l /path |cut -f10 -d" "|cut -f4 -d "-"

do you have any other solution?
Thanks,

2

try:

ls -l /path | tail -1 | sed 's/.*[-]//'
1 Like
3

In some hosts i have this kind of output

drwxr-xr-x 3 root root 4096 Sep 23  2010 mongodb-linux-x86_64-1.6.3
drwxr-xr-x 3 root root 4096 Feb 10  2012 mongodb-linux-x86_64-1.8.2
-rw-r--r-- 1 root root    0 Aug  8  2011 velocity.log

now if i would like to disregard the last line and just get the last number( in this case 1.8.2) what should I do?

Thanks,

4

try:

ls -l /path | grep "[-][0-9]" | tail -1 | sed 's/.*[-]//'
1 Like
5

Thank you this works perfect! :b: