How to find the one file and move destination using scripts in AIX?

Shell Programming and Scripting
1

I have a script which has two output formats in which i'am getting the two different output format in str1 and str2.So i want to get the output if the format is like str1 then i have to copy that into a directory or str2 format means it should be moved.This script i'am executing in shell script in aix server .so guys kindly help me out in this.

 
#!/bin/bash
source_path=/tmp
destination_path=/scripts
pwd
str1=`hostname`.`date "+%d%m%y%k"`* #str1 and str2 two format  files from/tmp
str2=Ma.`hostname`.`date "+%d%m%y%k"`*
source_path=$str1,$str2;
if [ $str1 ==  $str2 ]
then
echo "output is equal"
echo  mv "$source_path $destination_path"
else
echo "output is not equal"
echo  mv "$source_path $destination_path"
fi
exit 0

---------- Post updated at 02:54 PM ---------- Previous update was at 02:53 PM ----------

2

First correction would be use single = and not ==

3

I have change it and again not fine the file give the correct code.

4

Could you run your script as

sh -x script name

post the output?

5

The * is messing things up:

$ str1=`hostname`.`date "+%d%m%y%k"`*

I think you mean:

$ str1=`hostname`.`date "+%d%m%y%k"`