how to find a particular string from a set of string output

Shell Programming and Scripting
1

Hi ,

I have a line by line output as follows,for example output of ls

sample1
sample2
sample

i need to check if this output contains the exact string sample.If i use grep , it will find out all strings that contain sample as a part of their word.I dont want to do a pattern matching here but check if one of the line is equal to "sample" (a string comparison).How can i achieve this in shell scripting?

Thanks,
Padmini

2

uh, so maybe

ls | grep -e "^sample$"

?

3

Try this,

 

cat filename | while read input

do 

 if [[ "$input" = "string to be searched" ]]

 then

     #do some action if string match

 else

    # do some action if string does not match

 fi

done
4 
# grep --version
grep (GNU grep) 2.5.1-FreeBSD

#grep -w sample file
5

Hi,

what is "^sample$" ? am not able to understand this.

6

That's a regex, it tells:

^       #matches the null string at the beginning of a line
sample
$       #matches the null string at the end of a line

literally, search sample, nothing else.

7

Hi,

But am not getting the correct output if i use ls | grep "^sample$"

8

Try this,

cat filename | grep -w "sample"

9 
ls -1 | grep -ie "^String$"
10

Hi,

option 'x' will select only those matches that exactly match the whole line.
Eg:

     grep -x "my data" myfile

will select those lines from file myfile which exacly matches 'my data'.

Regards,

Ranjith

11

And what is the imput and real output , please use [code] tags when you post code or sample data.

12

EDIT : Too late �� (Why am I missing page n�s... ?_?)
Try grep with -w option:

~$ cat file
a
ab
abc
abcd
abcde

~$ grep abc file
abc
abcd
abcde

~$ grep -w abc file
abc