Hi All,
Below is the sample data of my files:
O|A|571000689|D|S|PNH|S|SI
sadm|ibscml1x|
I|A|571000689|P|S|PNH|S|SI
sadm|ibscml1x|
O|A|571000689|V|S|PNH|S|SI
sadm|ibscml1x|
S|C|CAM|D|S|PNH|R|ZOA|2004
bscml1x|
I|C|CAM|P|S|PNH|R|ZOA|2004
bscml1x|
O|C|CAM|V|S|PNH|R|ZOA|2004
bscml1x|
I need to extract the first column that only contain "I" only?
Please assists
Thanks
era
May 22, 2008, 4:17am
2
sed -n 's/^\(I\).*/\1/p' file
By "extract", do you really mean print only the first column? If not, maybe you mean
grep '^I' file
Dear era,
Thanks. It work.
Actually i'm looking to the first command:
sed -n 's/^\(I\).*/\1/p' file
Can u explain on this?
era
May 22, 2008, 5:14am
4
If the current line matches I at start of line (that's the caret ^), replace the whole line with just the part which matched (that's what the parentheses are for; they capture the match into \1) and print it.