Hi,
I need help to display the yesterday date in format mentioned below:
2012-06-26-PM
I tried this but it displays current date:
`date +%Y-%m-%d-%p`
explore http://www.unix.com/answers-frequently-asked-questions/13785-yesterdays-date-date-arithmetic.html
For linux (GNU date) Try.
date --date '1 day ago' +%Y-%m-%d-%p
Try this:
date +%Y-%m-%d-%p -d yesterday
I tried both but it gives me error:
date +%Y-%m-%d-%p -d yesterday
Error:date: 0551-402 Invalid character in date/time specification.
Usage: date [-u] [+"Field Descriptors"]
date --date '1 day ago' +%Y-%m-%d-%p
Error :date: Not a recognized flag: -
Usage: date [-u] [+"Field Descriptors"]
What OS version are you on since the Linux date utility is very powerful and can display dates in many formats depending on the supplied options...
AIX saturn 3 5 00044BB7D600
Ah, you mentioned "Linux" in the title. That took me in the wrong direction.
Try:
perl -le'print scalar localtime time - 86400 * shift' 1
Use 2 ... n to get n days ago:
% perl -le'print scalar localtime time - 86400 * shift' 1
Mon Jun 25 21:11:53 2012
% perl -le'print scalar localtime time - 86400 * shift' 366
Sun Jun 26 21:11:55 2011
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Yes,
I've fixed the title ...
1 Like