How to delete lines using sed?

Shell Programming and Scripting
1

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/ten
ServerName ten.com
</VirtualHost>

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/sachin
ServerName sachin.com
</VirtualHost>

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/yuvraj
ServerName yuvraj.com
</VirtualHost>

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/checking
ServerName checking.com
</VirtualHost
~

I want to delete sachin.com from the above file so the output look like

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/ten
ServerName ten.com
</VirtualHost>

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/yuvraj
ServerName yuvraj.com
</VirtualHost>

<VirtualHost 192.168.1.158:80>
DocumentRoot /home/checking
ServerName checking.com
</VirtualHost
~
Please how to do this using sed command

2

how about this awk code?

awk  '$0!~/sachin.com/' RS="\n\n" ORS="\n\n" file
3

Try with the opposite of a known sed oneliner ("print paragraph if it contains pattern"), I've adapted it to your
case ("print paragraph if it not contains pattern").

I'm not sure exactly how it works, but it does:

sed -e '/./{H;$!d;}' -e 'x;/sachin.com/d;' inputfile

or more compressed:
sed -e '/./{H;$!d;};x;/sachin.com/d;' inputfile

 Reference: http://sed.sourceforge.net/sed1line.txt

Regards

4

... and to avoid the adding of the empty new line you should use h instead of H for the first line.

sed '1{/./h;d;};/./{H;$!d;};x;/sachin.com/d;' infile
5 
awk 'BEGIN{RS="\n\n"}{if($6 != "sachin.com")print $0"\n";}' inputfile
6

If your grep supports -p flag.

 
grep -vp "sachin.com" inputfile