how to delete line with matching text and line immediately after

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1

hello experts,

I have a file: File1

Sample Test1
This is a Test
Sample Test2
Another Test
Final Test3
A final Test

I can use sed to delete the line with specific text

ie:

sed '/Test2/d' File1.txt > File2.txt

How can I delete the line with the matching text and the line immediately after.
so My resulting file would look like

File2:

Sample Test1
This is a Test
Final Test3
A final Test

thanks

2 
# echo "1\n2\n3\n4\n5\n6" | sed -e '/2/{N;d;}'
1
4
5
6
3

Hi.

Also:

% echo "1\n2\n3\n4\n5\n6" | sed '/2/,+1d'
1
4
5
6

According to man sed:

cheers, drl

4

Hmmm yes but that didn't work on my sed (AIX). YMMV!!!

5

Hi, gus2000.

The man page for the GNU version did not say that that was an extension. I'll try to see if that's POSIX. The version on FreeBSD 4.1 man page:

and the "+1" syntax also did not work there ... cheers, drl

6

shell:

#!/bin/sh
f=0
while IFS= read -r line
do 
 case $line in
   *pattern* ) f=1; continue ;;
 esac
 if [ "$f" -eq 1 ]; then   
    f=0 
    continue
 else
    echo $line
 fi
done <"file"

awk:

awk '/pattern/{getline;next}{print}' file
7

I used the awk suggestion below since I was already using awk for something else...It worked great

:slight_smile:
thanks