how to cut first 3 characters of each line in a file

Shell Programming and Scripting
1

Hi Friends

I have a file
like

sample1.txt
------------
10998909.txt
10898990.txt
1898772222.txt
8980000000000.txt

I need to take first 3 characters of each line in a file and i need to print it '
like loop

109
108
189
898

like this

Please help me in this.

Thank you guys
Krish.

2

Some possibilties:

cut -c 1-3 < sample.txt

or

sed 's/\(...\).*/\1/' sample.txt

awk '{print substr($0,1,3)|' sample.txt

Regards

3

Another way, you could do the following:

#!/bin/sh
cat sample1.txt | while read FILE
do
        SUBSTRING=${FILE:0:3}
        echo $SUBSTRING
done

Regards,
Drew

4

You can also try:

#!/bin/bash
cat sample1.txt| while read line
do
cut -b -3 |tee result.txt
done

5

Thank you
It help me a lottttttttttttt

Thanks
Krish.

6

What is the solution in other way?

cat file.dat
abcd2342398472394
xyxz430583490583409583409
qwet403985649056834430

need output as:
2342398472394
430583490583409583409
403985649056834430

  • Raveen O.
7

Got the solution.

awk '{print substr($0,5)}' file.dat

:b:

-Raveen O.

8 
cut -c5- file.dat