hi all
i am need to cut the name of the file which i am entering in the comand line. say abc.txt is the name of the file i need to cut only the "abc" part. when i try doing this(using cut -f1) i am getting the data that s present inside the file and the file name. pls help....
Try:
read filename
echo ${filename%%.*}
If you insist on using cut
echo "$filename" | cut -d. -f1
see man pages of cut for better understanding.
you should tell cut the field separator.
cut -d. -f1
there are many others ways also like sed,awk and with string operation within shell itself.
probably you might have tried
cut -d. -f1 abc.txt
what you need to do is
echo abc.txt | cut -d. -f1