How to count a number using awk?

Shell Programming and Scripting
1

hi, does any one know how to compare a file1 with many files and have to count a number (i.e. 1) like the following ..Thanx in advance

input

file1	file2	file3	filen
1	1	1	1
1	1	1	1
1	1	1	1
0	1	1	1
1	0	0	0
1	0	0	0
0	0	0	0
1	0	1	0

output

instances in file1 only - 2
instances in all files but not file1-1
instances in all files - 3
instances in none - 1
2

What have you tried?

3

I am doing some thing like this

awk '{print $1"_"$2"_"$3"_"$4}' $1 | awk '{h[$1]++}; END { for(k in h) print k, h[k] }' |grep -v file
4

One way to do it:

instances in file1 only:

paste file1 file2 file3 file4 | grep -c '^1[^1]*$'

instances in all files but not file1:

paste file1 file2 file3 file4 | grep -c '^0[^0]*$'

instances in all files:

paste file1 file2 file3 file4 | grep -c '^[^0]*$'

instances in none:

paste file1 file2 file3 file4 | grep -c '^[^1]*$'