how to convert array into the string

Hi
I have a line/string as follows:

A=" 3498 NORDEA - INDX LINKED NORY"

which was converted into an array of characters:

p321$ echo "${ARR[*]}"
3 4 9 8 N O R D E A - I N D X L I N K E D N O R Y

When I am trying print this array there are blank spaces between the letters. I am not sure why.... Is there a way to print this array so no blanks will be added btw the latters, another words how to convert this array to the original format (no blank between letters)

Thanks a lot for any advice....

doing 'man ksh' yields the following:

     The shell supports a one-dimensional array facility. An ele-
     ment  of  an  array variable is referenced by a subscript. A
     subscript is denoted by  a  [,  followed  by  an  arithmetic
     expression  (see Arithmetic Evaluation  below) followed by a
     ]. To assign values to an array, use set -A name value  ....
     The  value  of  all  subscripts  must  be  in the range of 0
     through 4095. Arrays need not be declared. Any reference  to
     a variable with a valid subscript is legal and an array will
     be created if necessary. Referencing an array without a sub-
     script  is  equivalent  to  referencing the element 0. If an
     array identifier with subscript * or @  is  used,  then  the
     value  for each of the elements is substituted (separated by
     a field separator character).

Tried resetting IFS to nothing?

If you just want to remove the spaces, send it the 'tr', and have it delete them.

echo "s t r i n g "| tr -d ' '

bd - I hope this helps.

use awk

awk 'BEGIN{
    A=" 3498 NORDEA - INDX LINKED NORY"
    m=split(A,a,"")
    for(i=1;i<=m;i++){
        print a
    }
}

or

# echo  "3498 NORDEA - INDX LINKED NORY" | awk 'BEGIN{FS=""}{for(i=1;i<=m;i++)print $i}'
string=$( printf "%s" "${ARR[@]}" )