How to check the varying file size

Shell Programming and Scripting
1

How to know a file is of fixed file or not over a span of time Actually my requirement is to check the size of the file in a specific directory for 60 seconds, and if it remains the same then I have to move to some other directory.Else I have to stop the execution. Request you to guide me in knowing the varying size of the file.

I got to know to calculate the file size with the following code:

 
 filesize=`ls -l output.txt |awk '{print $5 }'`
 echo $filesize

how to check it for 60 seconds?.

Thanks.,

2

sample

filesize=`ls -l output.txt |awk '{print $5 }'`
echo $filesize
sleep 60
filesize_2=`ls -l output.txt |awk '{print $5 }'`
if [ $filesize != $filesize_2 ]
then
  echo "not equal, it has changed"
fi
1 Like
3

use while loop

filesize=`ls -l output.txt |awk '{print $5 }'`
cnt=1
echo $filesize
while [1]
do
filesize_new=`ls -l output.txt |awk '{print $5 }'`
if [ $filesize -ne $filesize_new ]
echo "exiting the script"
exit 10
fi
if [ $cnt -eq 2 ]; then
mv output.txt sometoehlocation/output.txt
else
sleep 60
cnt=$(( cnt + 1 ))
fi
exit 0
done

cheers,
Devaraj Takhellambam

1 Like
4

You can use something like following :

# S=`ls -l b |awk '{print $5 }'`;P=0
# while [ $P -lt 60 ]
    do 
     size=`ls -l b |awk '{print $5 }'` 
      echo $size
     if [[ "$size" -ne "$S" ]];then 
          echo "Size has changed... Hence moving the file..."
          mv first_location  final_location
           break
     else  
           sleep 1
     fi
    P=`expr $P + 1`
    S="$size"
    done

:b::b:

1 Like
5

Thanks guys. The script is working fine:b: :slight_smile: