Juha
September 27, 2007, 2:14am
1
Hi,
How can I replace x first characters from a string?
I have a file with... say 10000 entries as follows:
00123456781
00123456782
00123456783
...
What I want to do is change the leading "00" with for example "12"
The leading 00 can be in some files some other 1 or more digits e.g. "1" or "123" or what ever.
What would be the most efficient way of doing this as there might be even 20.000.000 entries in one file.
I wonder if the method could be embedded to a oneliner such as:
perl -i -p -e "s/old/new/g" filename
Thanks!
juha:
Hi,
How can I replace x first characters from a string?
I have a file with... say 10000 entries as follows:
00123456781
00123456782
00123456783
...
What I want to do is change the leading "00" with for example "12"
The leading 00 can be in some files some other 1 or more digits e.g. "1" or "123" or what ever.
What would be the most efficient way of doing this as there might be even 20.000.000 entries in one file.
I wonder if the method could be embedded to a oneliner such as:
perl -i -p -e "s/old/new/g" filename
Thanks!
hey,
You can user sed.
sed 's/*/your replace string or number/' filename
I think you can use this when no. starts with 00* and in the starting of the line.
Otherwise you can use tr command to squeeze the multiple 0s.
visit: man tr
Thanks !!
Juha
September 28, 2007, 8:17am
3
Thanks I actually took the regular expression out your solution and included it into the perl one liner and it took 1.6 seconds to replace 1.000.000 entries!
Thanks for your help