How to capture a string enclose by a pattern within a file?

Shell Programming and Scripting
1

Hi all,

My file :test.txt just like this:

...........................

From: 333:123<sip:88888888888@bbbb.com
To: <sip:123456@aaaaa.com

.........................

I want a script to capture the string between sip: & @

Expect output:

88888888888
123456

Please help!

2

Try something like:

sed 's/.*sip://;s/@.*//' test.txt
1 Like
3

In awk

$ awk 'gsub(".*sip:|@.*",x)' file

88888888888
123456

In Perl

$ perl -pe 's/.*sip:|@.*//g' file

88888888888
123456

Using Grep

$ grep -Po '(?<=sip:).*(?=@)' file

88888888888
123456
1 Like
4

Great!
Many thanks for Don & Akshay.

5

Some more awk
awk -F"sip:|@" '{print $2}' file

gnu awk
awk '{print gensub(/.*sip:(.*)@.*/,"\\1","g")}' file

1 Like