how to append into array thru awk

Shell Programming and Scripting
1

hey champs,

i have variable as field_dtls,
which has values like
CLIENT ID|FAMILY NAME|MIDDLE NAME|FIRST NAME|COUNTRY NAME|ADDRESS|NATIONAL ID|PASSPORT NUMBER

so,
echo "$field_dtls"
CLIENT ID|FAMILY NAME|MIDDLE NAME|FIRST NAME|COUNTRY NAME|ADDRESS|NATIONAL ID|PASSPORT NUMBER

but i could not fragments these values into arrays based on field separator |

for i in `echo "$field_dtls" | awk -F"|" '{ for (i=1;i<NF;i++) { printf("%s\n",$i)}}'`
> do
> j=1
> var[$j]="$i"
> j=`expr $j + 1`
> done

if i am printing echo ${var[1]}
it showing me o/p as ID

how can i overcome this......e.g echo ${var[1]} should give CLIENT ID

2 
"`echo "$field_dtls" | awk -F"|" '{ for (i=1;i<NF;i++) { printf("%s\n",$i)}}'`"
3

thanx a lot.....
i did it in some other way....
awk '{c=split($0, s); for(n=1; n<=c; ++n) print s[n] }' $1