How to add certain pattern to an output..?

Applications UNIX Desktop Questions & Answers
1

Hi Everyone

If i do this

cat /usr/local/data/sales/taxware/indata/stepprod |wc -l

i'll get output like this

5

And now i want to add a word for this output 'stepprod' (no quotes, only word) like below

stepprod 5

Thank you

2 
cat /usr/local/data/sales/taxware/indata/stepprod |wc -l | xargs echo stepprod
1 Like
3

This is an other way to do it:

 echo stepprod `cat your_file |wc -l`
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4

No need to use cat:

echo "stepprod $( wc -l < file )"
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5

Or, may be a bit more flexible:

FN=/usr/local/data/sales/taxware/indata/stepprod
echo ${FN##*/} $( wc -l < $FN )
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6

hi arun if follow your answer iam getting output like....
stepprod a b c d e f g h i j k l
but i need the total count of my file.. it means i want output like below
stepprod 12

Thank you for your reply

7

If you skip the unneeded calls to cat and don't care about whether the filename comes before or after the line count, it would be much more efficient to just use:

wc -l /usr/local/data/sales/taxware/indata/stepprod

which with your sample data would produce something like:

       5 /usr/local/data/sales/taxware/indata/stepprod

or:

cd /usr/local/data/sales/taxware/indata/
wc -l stepprod

which would produce something like:

       5 stepprod

And, if you have more than one file to count:

wc -l stepprod file2 file3

might give you something like:

       5 stepprod
      12 file2
    1000 file3
    1017 total
8

To get exact ouptu as you want with the the file name for which you are trying to get,

 
awk '{ line++; } END { print FILENAME" "line}' filename