ls xx > yy.log
echo $? can get the return value of "ls xx"
but if I use
ls xx |tee -a yy.log
I can't get the return value of "ls xx", and I get the return value of the whole cmd "ls xx |tee -a yy.log", it is always "0"
my question is how could I get the return value of "ls xx" using "tee" to get the log