how do i pattern match a field with awk?

Shell Programming and Scripting
1

hi,

let's say $numbers = "324 350 587" an so on...
what i'm trying to do is this:

awk -v numbers="$numbers" '{if (numbers ~ /$2/) print $0, "bla bla"}' file

# file looks like this:
214 .....
215 ...
216 ....
250
...
324
325
...
350 something ...
...
587 ...

i want to do something with the lines that contain the numbers in the variable numbers, and something else with the lines that match other patterns.

thanks..

2

not sure what you're after....
Is it: if the line contains one of the numbers, then 'blah blah'?

3

forgot to mention - the line i wrote didn't work i guess it has to do with the syntax

and yes, what i meant to do was:
if the line contains one of the numbers (in the 2ed field), then print $0, "..something...."

4

nawk -f some.awk myFile
OR
nawk -v numbers='324 350 587' -f some.awk myFile

some.awk:

BEGIN {
  if (numbers =="") numbers="12 13"
  gsub("[0-9]+", "(^&$)", numbers)
  gsub(" ", "|", numbers)
}

$2 ~ numbers { print $0, "blah blah" }
5

omg, isn't there a simple way to do this?

how can i make awk recognize the second field as a pattern?

this doesn't work:
awk -v numbers="$numbers" '{if (numbers ~ /$2/) print $0, "bla bla"}' file

but this works (when i put actual number):
awk -v numbers="$numbers" '{if (numbers ~ /345/) print $0, "bla bla"}' file

how should i write it so that awk will "see" the actual number that is in the file (in the 2ed field)??

thanks so much for trying to help.