How do i grep a pattern from part of LINE

UNIX Solaris
1

Hi how do i grep only a part of the line from a file from all the lines.

file:
asdfgh 543212376 nag
lkjh abhilash 543757858

How do i grep and print only 543212376 and 543757858

Can i grep something like 543* and print only that.

2

use grep and pipe it thru to either cut or awk

3

sed may be a better option

sed 's/^.*\(543[0-9]*\).*$/\1/' file
4 
while read line
do
  for items in $line
  do
    case $items in 
    543* ) echo $items ;;
    esac    
  done
done < "file"