How can i passed a parameter to a file?

Shell Programming and Scripting
1

i got a file called Pass1, and then i need to passed a number to my script with the '-p pass_mark' option.

Example type
Pass1 -p 18

to pass 18 to my script for comparing things, so how can i do it?

2

If you want named parameters, check up on the getopts function (available in a ksh and bash near you)
If you only want to pass any parameter, they are automagically stored in $1 to $9 individually and $*/$@ collectively.

3

example:

whie getopts "p:" opt
do
case $opt in
p) pass_mark = $OPTARG ;;
esac
done

In your cass to pass , just the mark, you could just run the script as

scriptname 45

and then in your script, accept

pass_mark=$1

cheers,
Devaraj Takhellambam
shift $((OPTIND -1))

4

Thank you

5

i did somethings like that, but is not working

while getopts "p:" opt
do
case $opt in
p) pass_mark = $OPTARG ;;
esac
done

pass_mark=$1

if [ 50 -lt $1 ]
then
echo "50 is less than $1"
else
echo "50 is not less than $1"
fi
6

can i use other command in stead of getopts?

7

Yes you could just use a command line parameter.

In your script

pass=$1
if [ $pass -lt 50 ]; then
echo "Pass mark of $pass is less than 50"
else
echo "Pass mark of $pass is greater than 50"
fi

Run the script as

scriptname 45

cheers,
Devaraj Takhellambam

8

but if i have a default pass mark then what can i do? if people just run "scriptname" without anything after the scriptname, so what can i do for it??