How can I get the 3 consecutive appearances of a line?

Shell Programming and Scripting
1

File 1

aaa
ccc
fff

File 2

aaa
bbb
ddd

File 3

aaa
bbb
eee

File 4

bbb
ggg

Output should be:

aaa
bbb

Thank you.

2

Your question is not clear and explained. Be clear with you question and use code tag.

3 
cat file* | sort | uniq -c | head -2

If you dont want you can remove the count

1 Like
4

Thanks for this but I tried it but still it includes the line even it skips a certain file. That is to say,

File 1 - aaa
File 2 - aaa
File 3 - no "aaa"
File 4 - aaa

The output was:

3 aaa

Wherein it should not output the "aaa" because its appearances are not consecutive. Thanks in advance.

5

How about this..

awk '{a[$0]++} END { for (i in a) { if (a==3) print i}}' file*

EDIT : Ignore this solution. Doesn't meet the "consecutive" requirement you provided.

1 Like