hide stdout but need exit status

Shell Programming and Scripting
1

Hi:

echo "Escriba el nombre de usuario: \c"
read user

lsuser -a $user 2>/dev/null || (echo "Usuario no valido en el sistema. Abortando." &&  exit 1)

I want:

  • If 'lsuser -a $user' fails, script exits but hide stderr.
  • If 'lsuser -a $user' succeeds, script continue, and hide stdout.

thx in advance
Israel.

2

1>/dev/null at the end of your statement which outputs to the screen.

3

but if I use 1>/dev/nulll when 'lsuser -a $user' fails I see stderr on screen...I want to hide stderr or stdout on both ways (fails or succeeds)

regards
Israel.

4 
lsuser -a $user 2>/dev/null 1>/dev/null
5 
lsuser -a $user 1>/dev/null 2>/dev/null
6

Maybe

lsuser -a $user >/dev/null 2>&1 || (echo "Usuario no valido en el sistema. Abortando." && exit 1)
7

umm.. there is something odd here... I realized the problem is in (echo "Usuario no valido en el sistema. Abortando." && exit 1) string... if I use:

lsuser -a $user >/dev/null 2>&1 || exit 1 it works

do you know why?
I'm using ksh93 on AIX.

thanks again

8

Try without running a subshell: use {} in state of (). You can write &>/dev/null to redirect both stdout and stderr

lsuser -a $user &>/dev/null || { echo "Usuario no valido en el sistema. Abortando." && exit 1 }
9

sorry the delay...frans

I tried with { } but it doesn't work on my aix..:frowning:

another example:

grep "$user:" /etc/security/user.roles || (echo "El usuario no tiene roles asignados" && exit 1)

here, exit status is always 1, even if grep if OK or not

What am I missing here? How can I make an echo AND exit if grep fails?

thanks a lot

10

Try ';' instead of '&&'

grep "$user:" /etc/security/user.roles || (echo "El usuario no tiene roles asignados" ; exit 1)
11

well... this way works but I dont know really how

grep "$user1:" /etc/security/user.roles 1>/dev/null || echo "El usuario no tiene roles definidos" && (exit 127)

regards