Help with variable using loop

Shell Programming and Scripting
1

Hi

I have webserver that I do read data from.
Data are stored like this:

Huston |1
Portland |2
Hazen |1
Minneapolis |4
Albany |1
Pittsburg |1
Albany |1
Huston |1
Portland|1
Hazen |2
Albany |2
Huston |1
Hazen |1

Script

#!/bin/sh
user="admin"
pass"demo"
server="192.168.1.10"
port="80"
url="http://$user:$pass@$server:$port"

# List of location to log
LOC1="Huston"
LOC2="Hazen"


case $1 in
   config)
        cat <<'EOM'
graph_title Information
graph_vlabel Number
graph_category Data
Count01.label 01 $LOC1
Count02.label 02 $LOC2

EOM
        exit 0;;
esac

# read data into variable
infoservers=`wget -q -O - "$url/folder"`

echo -n "Count1.value "
echo "$infoservers" | grep "|1" | grep $LOC1 | wc -l

echo -n "Count2.value "
echo "$infoservers" | grep "|1" | grep $LOC2 | wc -l

Output

Count1.value 3
Count2.value 2

This list number of |1 in table from the data I like to get value from.
I have tried to make a loop to do the same, so I do not need to add more lines than the location to look at. I can not get script to show value.

for i  in `seq 1 2`;
do
       
        echo  -n "Count${i}.value "
	 echo "$infoservers" | grep "|1" | grep $LOC${i} | wc -l
done
2

Well, all the $val are evaluated at once, so $LOC is unknown. You can call eval to get another look, like:

eval grep '$loc'"$i{i}"

The first pass expands clearing quotes, for i=1, to:

eval grep $LOC1

and then eval runs, expands $LOC1 and runs grep with that arg.

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