Help with the syntax

Shell Programming and Scripting
1

can anyone explain the code for me... i am new to shell programming

while getopts ":S:D:U:" OPTION "$@"
do
case $OPTION in
S) SRVR=$OPTARG;;
D) DB="$OPTARG"; USEDB="use $OPTARG";;
U) UID=$OPTARG;;
:slight_smile: MISSINGOPTARG="$MISSINGOPTARG -$OPTARG";;
?) if [ "$OPTARG" = "?" ]
then
HELP=1
else
UNEXPECTEDOPT="$UNEXPECTEDOPT -$OPTARG";
fi;;
esac
done

2

HI,

while getopts ":S:D:U:" OPTION "$@" --->The possible options are specified 
                                                         here
do
case $OPTION in 
S) SRVR=$OPTARG;;    -->Handling the option S -->OPTARG will have the 
                                    value for the oprion S
D) DB="$OPTARG"; USEDB="use $OPTARG";;
U) UID=$OPTARG;;
:) MISSINGOPTARG="$MISSINGOPTARG -$OPTARG";;
?) if [ "$OPTARG" = "?" ]
then
HELP=1
else
UNEXPECTEDOPT="$UNEXPECTEDOPT -$OPTARG";
fi;;
esac  --->End of switch /case
done

Thanks
Raghuram

3

Thanks for ur help