Help with ls, grep commands

Shell Programming and Scripting
1

Oracle Linux 6.4/Bash shell

I have six files as shown below. Using ls/grep (or anything) , I need to list all files which start with the pattern

stomper

but not the ones
which ends with 1.

$ touch stompera
$ touch stomperb
$ touch stomperc
$ touch stompera1
$ touch stomperb1
$ touch stomperc1
$

$
$ ls -l stomper*
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stompera
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stompera1
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stomperb
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stomperb1
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stomperc
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stomperc1

### This is what I've tried. It isn't working
$ ls -l stomper* | grep -v 1
$

$ ls -l stomper* | grep stomper | grep -v 1
$

Expected output:

-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stompera
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stomperb
-rw-r--r-- 1 stack clsapp 0 Apr 11 09:29 stomperc
2

try:

 ls -l stomper* | grep -v '1$'
1 Like
3

Thank you Jim

4

If you know that there is at least one matching file, you could also try:

ls -l stomper*[[:lower:]]

if you're interested in files starting with stomper and ending with a lower case alphabetic character:

ls -l stomper*[a-c]

if you want filenames starting with stomper and ending with a , b , or c , or:

ls -l stomper*[!1]

if you want filenames starting with stomper and ending with anything other than 1 .

1 Like
5

Thank you Don. Thanks everyone

One more thing.
I am a beginner in regular expression stuff. I tried to use ^ character to list the file names starting with 1.
It doesn't seem to work. Following is what I've tried

touch stompera
touch stomperb
touch stomperc
touch 1stompera
touch 1stomperb
touch 1stomperc

$ ls -l
total 0
-rw-r--r-- 1 strp nhuy 0 Apr 12 22:15 1stompera
-rw-r--r-- 1 strp nhuy 0 Apr 12 22:15 1stomperb
-rw-r--r-- 1 strp nhuy 0 Apr 12 22:15 1stomperc
-rw-r--r-- 1 strp nhuy 0 Apr 12 22:14 stompera
-rw-r--r-- 1 strp nhuy 0 Apr 12 22:14 stomperb
-rw-r--r-- 1 strp nhuy 0 Apr 12 22:14 stomperc

$ ls -l | grep '1^'
$
$ ls -l | grep '^1'
$
6

Something like this?

ls -l 1*
1 Like
7

ls -l prints the filename last, and it prints permissions first. That is why grep '^1' does not work, because none of the lines start with 1 , they start with -

1 Like
8

Shi@#$%. Why didn't I think of that ?