Help With Loop in Case Statement script

Shell Programming and Scripting
1

I am writing a bash script that asks the user for input and I need it to repeat until the user selects quit.. I dont know how to write the loop for it I searched all over but i still do not get it.. if anyone could help with this it would be greatly apprciated here is my script so far:

#! /bin/bash

if [[ $@ == "username" ]]
then
	echo "Hello, $@!"
	echo "The current directory is $PWD"
	echo "The home directory is $HOME"
else
	echo "Hello Stranger"
fi

echo "Would you like to:"
echo "1) See your name"
echo "2) See your current directory"
echo "3) See your home directory"
echo "4) Quit"
read case;

case $case in 
1) echo "username";;
2) echo "$PWD";;
3) echo "$HOME";;
4) echo "Quit";;

esac 

rep="$case" 

#THIS IS WHAT I DONT GET: it just runs this command like 5 times but does not let me choose a option 

while (( $rep <=1 )) 
do 
echo "Would you like to:"
echo "1) See your name"
echo "2) See your current directory"
echo "3) See your home directory"
echo "4) Quit"
rep=$(( rep+1))
done

I really need help figuring this out

2

Try this:

while true
do
    echo "Would you like to:"
    echo "1) See your name"
    echo "2) See your current directory"
    echo "3) See your home directory"
    echo "4) Quit"
    echo -n ">> "
    read case

    case "$case" in
        1) echo "username";;
        2) echo "$PWD";;
        3) echo "$HOME";;
        4) break;;
    esac
done

echo "Quit"
1 Like
3

hergp Thank you so much man this really helped me out :smiley: