Help with awk in array in while loop

Shell Programming and Scripting
1

Hi everyone:)
I have 2 files - IN & OUT. Example:

IN
A:13:30
B:45:40
.
.
. UNLIMITED

OUT
Z:12:24
Y:20:15
.
.
. UNLIMITED

I want first row of numbers of IN - OUT. Example 13-12 45-20
My code is

#!/bin/csh -f
set y=1
while ( $y<UNLIMITED )
set in = `awk -F':' '{print $2}' IN |awk '{array[NR]=$0} END {print array[y];}'`
set out = `awk -F':' '{print $2}' OUT |awk '{array[NR]=$0} END {print array[y];}'`
set number = `expr $in - $out`
echo "$number"
@ y = $y + 1
end

expr: syntax error
expr: syntax error
expr: syntax error
expr: syntax error
expr: syntax error
expr: syntax error
all is expr: syntax error
I tried to solve more than one day already.:confused: And also duno wat should i write instead of UNLIMITED.
Anyone can help me?

2

As a starting point, you may want to review the following, http://www.unix.com/shell-programming-scripting/105029-awk-program-3.html#post302298986

Files are read into a two-dimensional array and then processed for printing.

The original query was to extract the 5th column from multiple files and print them out in columnar format.

3

Please put code inside

 tags.


 
#!/bin/csh -f

[/quote]
csh is not recommended for scripting.

[indent]Top Ten Reasons not to use the C shell
Csh problems
Csh Programming Considered Harmful

cut -d: -f2 in > in.tmp
cut -d: -f2 out > out.tmp
paste -d- in.tmp out.tmp
rm in.tmp out.tmp