help me out...

Shell Programming and Scripting
1

i am ahving following file

thanks,
vidya...

2

There is an example on the perlop man page which is simpler:

# Delete (most) C comments.
$program =~ s {
    /\*     # Match the opening delimiter.
    .*?     # Match a minimal number of characters.
    \*/     # Match the closing delimiter.
} []gsx;
3

is there any unix command??
i don't wana go for perl.. and in AIX perlop is not available...

4

Without perl multi-line regex capability I don't think you'll be able to simplify it too much... unless you change RS in awk maybe? I might try that next. Here is an awk solution, but as you can see it's not short:

awk '
        /\/\*.*\*\// { gsub("/\*.*\*/",""); print; next }
        /\/\*/ { gsub("\/\*.*",""); print; incomment=1; next }
        incomment && /\*\// { gsub(".*\*\/",""); incomment=0; print }
        incomment { next }
'

It does not work for situations where there are multiple comments on a line, e.g. the following:

 some code; /* a comment */ some more code; /*another comment */

would become:

 some code;
5

This works better:

awk -v RS='^Y' ' { gsub("/\*.*\*/",""); print; }'

However also doesn't handle multiple comments on a line. You could make it safer like this:

awk -v RS='^Y' ' { gsub("/\*[^*]*[^/]*\*/",""); print; }'

The only situation that does not handle well is a /* comment * like / this */, which I guess would be pretty rare.

(Incidentally, ^Y is just a randomly chosen, rarely used control character, entered using Ctrl-V Ctrl-Y.)