Help in while loop

Shell Programming and Scripting
1

I have below code, that check abcd that is fine, when it not find abcd it check for 1 minutes that is also fine but i want one enhancement when it failed at the end it print "please check again" but if i add this line after fi statement it is constantly printing, i don't want that, please suggest.

tp=1
while [ $tp -le 2]

do

  echo 

  command=`ls -l |grep abcd`

  if [ "$command" == "123" ]

  then

  echo "ok"

  break

  else
  let tp++
  sleep 30
  echo "nook"

  fi

done
2

You could check the value of $tp (which will be 3 if you fail) before outputting your warning message. Alternatively, explicitly set a variable inside the 123 check to indicate that you succeeded, and check that.

3

... or test the ok condition again.
But I wonder how something that matches "abcd" can ever be "123".

4

how i can test the ok condition again? Please update the code.

5

To check condition again you can use infinite loop something like this

#!/bin/bash
x=0
while : 
do

n=0
while [ $n -le 5 ];do 

if [ $n -eq  3 ]; then
    echo "Going to Break internal while loop but will check again" $x
    break
fi

n=$((n+1))

done
x=$((x+1))
done
6 
tp=1
while [ $tp -le 2]
do
   ...stuff...
done

if [ "$command" != "123" ]
then
   echo "a warning message"
fi